In the figure alongside, seg AO ≅ seg BO, m(arc AC) = 124° and ∠COB = 64° find m(arc AO) 
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We know, the angle subtended by an arc of a circle at the centre is double the angle subtended by it at any point on the remaining part of the circle
Hence,In given circle,
∠POR=2∠PQR
Therefore ∠POR=2×40^o =80^o
Step-by-step explanation:
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