in the figure angle abc equal to 69 degree and Angle ACB equal to 31, find angle BDC
pranjal7:
Where is the figure?
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2
Where is the fig ???
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4
Hello mate =_=
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Solution:
∠ABC+∠ACB+∠BAC=180°
⇒69°+31°+∠BAC=180°
⇒∠BAC=180°−69°−31°=80° ........(1)
∠BAC=∠BDC (Angles in the same segment are equal) .......(2)
From (1) and (2), we can say that
∠BDC=80°
hope, this will help you.
Thank you______❤
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