Math, asked by deo9, 1 year ago

In the figure angle ABD = 3 angle DAB and angle bdc = 96 degree, find angle ABD

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Answered by pradnya250604

12

Answer:

in ΔABD

∠ABD+∠DAB=∠BDC (EXTERIOR ANGLE PROPERTY)

∠ABD+1/3 ∠ABD=96

4∠ABD/3= 96

4∠ABD=288

∠ABD= 72°

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