in the figure angle B=90degree ,angle A=angle C and BC=10cm,then find the value of tan 45degree
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Answer:
Draw a right angled △ABC using given instructions:
Here sin30=
AC
BC
2
1
=
20
BC
Or BC=10 cm
By Pythagoras theorem:
(AB)
2
=(AB)
2
−(BC)
2
=(20)
2
−(10)
2
=300
AB=10
3
cm.
solution
Answered by
0
Let angle be angle A and Tan A be 45°
therefore angle A = 45°
Tan 45= opposite side/ adjacent side
= BC/AB
1 = 10/AB
1 × AB = 10
Therefore AB= 10
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