Question

In the figure angle BAD=3 angle DBA, find angle CDB, angle DBC and angle ABC.​

Answer 1

Answer:

Angle CDB + angleBDA =180°

angle CDB =180°-104°=76°

angle BCD +angleDBC = angleBDA

65° + angleDBC =104°

angle DBC=104°-65°

angle DBC=39°

angle A + angle B+ angle C=180°

3 angle DBA + angle DBC + angle DBA +65°=180°

4 angle DBA + 39°+65°=180

angle DBA =180-104/4=76/4=19

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