In the figure angle MNP =90 degree
seg NQ is perpendicular to seg MP
MQ=9
QP=4
Find NQ
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We know that,
In a right angled triangle, the perpendicular segment to the hypotenuse from the opposite vertex, is the geometric mean of the segments into which the hypotenuse is divided.
∴ QN²=MQ×QP
=9×4
QN=√ 36
=√ 36
=6
Hence, NQ = 6.
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