How many A particle falling under gravity describes 80 ft in a certain second.How long does it take to describe the next 112 ft?
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Explanation:
Let us consider the velocity of particle when it completes 80 ft is v
and this velocity will be initial velocity for the 112 ft height. let us
consider it takes t time.
g = 32 ft/s^2
v^2 = u^2 + 2gh
v^2 = 0^2+ 2* 32* 80
v = √(64*80)
v = 8x4√(5)
v = 71.55 ft/s
now h = vt+0.5 x g x t^2
112 = 71.55t+0.5 x 32 x t^2
On solving
t = -b ±√(b^2-4ac) / 2a
t = 1.2 sec
i hope it will help you
regards
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