in the figure AQ, AR and BC are tangents to a circle with centre O. if AB=7cm ,BC= 5cm, AC=5cm then length of the tangents AQ is
suryacube76:
ritesh i think you forgot to give the diagram
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Since all the sides of the triangle are not unequal we can say that the triangle is a scalene triangle....
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Explanation:
AQ, AR and BC are tangents to a circle with centre O
AB=7cm ,BC= 5cm, AC=5cm
If you consider BS = X and CS = 5X. The tangent that is drawn from the exterior of the circle would be equal and the length of the tangents AQ would be equal to AR Answer - A. 7.5 cm
Construction - Draw line segment AD on triangle ABC.
We know, tangents drawn from an external point are equal.
Therefore,
AP = AQ
BP = BD
CQ = CD
Now,
Perimeter of the triangle ABC = 5 + 6 + 4 cm = 15 cm
AB + BC + AC = 15 cm
AB + BD + CD + AC = 15 cm (since BD + CD = BC)
AB + BP + CQ + AC = 15 cm
(AB + BP) + (CQ + AC) = 15 cm
AP + AQ = 15 cm
AP + AP = 15 cm
2AP = 15cm
AP = 15÷2 cm
AP = 7.5 cm
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