Question

In the figure area of the rectangle 20 sq cm. then , a) what is the area of the of the triangle ABC? b) what is the area of the triangle BPC? ​

Answer 1

Answer:

In right △AED, using Pythagoras theorem,

AD

2

=AE

2

+DE

2

=9

2

+12

2

=81+144=225cm

⇒AD=

225

=15cm=diameter

Required area = ar. ABCD + ar. semi-circle - ar △AED=(20×15)+

2

1

×

7

22

×(

2

15

)

2

−

2

1

×9×12

=300+88.3928−54=334.3928cm

2