Question

in the figure B < A and C<D. show that AD < BC​

Answer 1

Step-by-step explanation:

THIS IS THE ANS OF YOUR QUESTION AND MARK IT AS THE BRAINLIEST ANSWER.

Answer 2

$\huge\mathfrak{Bonjour!!}$

$\huge\bold\pink{Answer:-}$

⏩ Given:-

* angle B < angle A

*angle C < angle D

⏩To Prove:-

* AD < BC

⏩Proof:-

It's given that,

angle B < angle A

Therefore,

OA < OB.....→ (i) [Side opposite to greater angle is longer]

Now,

In ∆ COD,

angle C < angle D (Given)

Therefore,

OD < OC....→ (ii)

Now,

On adding (i) and (ii), we get,

OA + OD < OB + OC

=> AD < BC

HENCE PROVED...!!!

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