In the figure BC\\AD find the values of x,y and z
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Answered by
1
Answer:
DE parallel to BC and AB is a transversal.
∴ ∠ADE=∠DBE⋯⋯[corresponding angles]
⇒ x=30o
Now, DE parallel to BC and AC is a transversal.
∴ ∠AED=∠ECB⋯⋯[corresponding angles]
⇒ y=40o
In triangle ABC,
∠A+∠B+∠C=180o
⇒ z+30o+40o=180o
⇒ z=180o−40o−30o
⇒ z=110o
Therefore,
⇒ x=30o
⇒ y=40o
⇒ z=110o
Answered by
2
x=70,y=80,z=30
Step-by-step explanation:
x+y+z=180. (linear pair)
x+80+30=180
x+110°=180°
x=180-110
x=70°
y=80°(alternate interior angle)
x+y+z=180(angle sum property)
70+80+z=180
150+z=180
z=180-150
z=30°
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