Math, asked by nmamatha0709, 5 hours ago


In the figure BC\\AD find the values of x,y and z

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Answers

Answered by ekaur0796
1

Answer:

DE parallel to BC and AB is a transversal.

∴ ∠ADE=∠DBE⋯⋯[corresponding angles]

⇒ x=30o

Now, DE parallel to BC and AC is a transversal.

∴ ∠AED=∠ECB⋯⋯[corresponding angles]

⇒ y=40o

In triangle ABC,

∠A+∠B+∠C=180o

⇒ z+30o+40o=180o

⇒ z=180o−40o−30o

⇒ z=110o

Therefore,

⇒ x=30o

⇒ y=40o

⇒ z=110o

Answered by ruchithakur8867
2

x=70,y=80,z=30

Step-by-step explanation:

x+y+z=180. (linear pair)

x+80+30=180

x+110°=180°

x=180-110

x=70°

y=80°(alternate interior angle)

x+y+z=180(angle sum property)

70+80+z=180

150+z=180

z=180-150

z=30°

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