Question

|Z1×Z2|=|Z1|×|Z2| Prove this ​

Answer 1

Given that ∣z1+z2∣=∣z1−z2∣

Squaring on both side gives,

∣z1∣2+∣z2∣2+2Re(z1z2ˉ)=∣z1∣2+∣z2∣2−2Re(z1z2ˉ)

⇒Re(z1z2ˉ)=0

⇒arg(z1z2ˉ)=2π

⇒arg(z1)+arg(z2ˉ)=2π

⇒arg(z1)−arg(z2)

Answer 2

Answer:

For your question this the answer

↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓

Step-by-step explanation:

Let Z be 10

Then |Z1×Z2|=|Z1|×|Z2|→|(10×1)×(10×2)|=|(10×1)|×|(10×2)|

»|10×20|=|10|×|20|

»|200|=|200|

»200=200

Hence,|Z1×Z2|=|Z1|×|Z2| →_-_Prooved _-_←