Question

The Area of the triangle with
vertices (1, 2); (5, 7) and (3,8) is​

Answer 1

This is your answer.

I hope you may like it.

Mark it as brainliest answer.

Answer 2

SOLUTION:-

⠀⠀

Answer

⠀

⠀⠀ • Area = 7 sq. units

⠀⠀

Given

⠀⠀

⠀⠀ • Vertices (1,2), (5,7)and (3,8)

⠀⠀⠀

To Calculate

⠀⠀⠀

⠀⠀ • Area of triangle

⠀

Step by step Explanation

⠀⠀⠀⠀

⠀⠀⠀⠀ ☆ Using Formula

⠀⠀⠀⠀

$| \frac{1}{2} \: {x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)}|$

⠀⠀

The coordinators of the vertices of the Given triangle are

A(1,2) = x1 , y1

B(5,7) = x2 , y2

C(3,8) = x3 , y3

⠀⠀

Putting values,

Area = 1/2| x1(y2-y3)+x2(y3-y1)+x3(y1-y2) |

➡️ 1/2 | 1(7-8)+5(8-2)+3(2-7) |

➡️ 1/2 | 1×(-1)+5×(6)+3×(-5) |

➡️ 1/2 | -1+30-15 |

➡️ 1/2 | -16+30 |

➡️ 1/2 | 14 |

➡️ 14/2

➡️ 7 sq. units

⠀⠀

Hence,

⠀⠀

⠀⠀ • Area of triangle = 7 sq. units

________________________________________________

⠀⠀

☆ Add for your knowledge ☆

⠀⠀

Three points A(x1,y1) , B(x2,y2) and C(x3,y3) are Collinear only when x1(y2-y3)+x2(y3-y1)+x3(y1-y2)=0

⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀____________________