in the figure BD is equal to p a is equal to PD area of triangle ABC hundred centimetre square what is the area of triangle PAB
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A median divides a Triangle into 2 triangles of equal areas.
It is given, BD=DC.
Therefore, AD is the median of ΔABC
⇒ ar.(ΔABD)=ar(ΔACD)
It is given, PA=PD
Therefore BP is the median of ΔABD
∴ ar(ΔBPD) = ar(ΔBPA)
⇒ar(ΔPAB) = 1÷2ar(ΔABD)
ar(ΔPAB) = 1/2ar(1/2ΔABC) (∵ΔABD area is half of ΔABC(proved above))
∴ar(ΔPAB) = 1/4ar(ΔABC)
⇒ar(ΔPAB) = 1/4×100 (∵ ar(ΔABC) = 100cm²)
⇒ar(ΔPAB) = 25 cm²
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