Question

In the figure below,D and E are the mid points of AB and AC respectively.Show that: AF = FG.

Answer 1

hey there!! here is ur solution...

In ΔABC,
D and E are the mid points of ΔABC
so, By mid point theorem..
DE ¦¦ BC__________(1)

in ΔABG,
D is the mid point and DF ¦¦ BG (from 1)
so, By converse mid-point theorem..
F is also the mid point of side BG

since, AF = FG [F is the mid-point proved above]

"proved"

hope it works 4 u...

Answer 2

Step-by-step explanation:

given AD = BD

AE = CE

to prove AF = GF i.e DE bisects AG

proof in triangle ABC , DE is parallel to BC (1)

in triangle BCG, D is the midpoint (given)

DE is parallel to BC (from 1)

DE bisects AG (converse mid point theorem) (2)

AF =FG (from 2)

hence proved