In the figure BM and DN are both perpendicular tothe segment AC and BM=DN prove that AC bisects BD
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11
Answer:
I tried to keep it simple, hope it helps
Step-by-step explanation:
In triangle BMO and triangle DNO
ANGLE BOM = vertically opposite angle DON
Angle OMB = Angle OND = 90 degree.
BM = DN [Given]
The triangles are congruent by AAS.
OB = OD
MN bisect BD
Therefore, AC bisects BD.
Answered by
6
Answer:
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