Question

In the figure, BP: PQ: QC = 1:2:1. Area of triangle APQ is 8 sq.cm.
i) Find the area of triangle ABP
ii) Find the area of triangle ABC

Answer 1

Answer:

Correct option is

C

1 : 9

If AP:PB=1:2 then AP:AB will be 1:3.

So, in similar triangles, the ratio of the area of

ΔABC

ΔAPQ

=(

3

1

)

2

=

9

1

Answer 2

Your question is correct but it is incomplete without the diagram.

Refer the attachment for the diagram.

The area of triangle ABP is 4sq.cm

The area of triangle ABC is 16sq.cm

Given

Area of triangle ABQ = 8cm2

BP : PQ = 1 : 2

a) Area of triangle ABP

=1 / 2 area of triangle ABQ

=1 / 2 * 8

4cm2

b) Area of triangle ABC

Area of (triangle ABP + Triangle APQ + Triangle AQC)

=4 + 8 + 4

= 16

16cm2.