Question

In the figure, CB & AD are perpendicular to AB. If AD=7cm, BC=5cm

and area of ∆BOC=150 sq.cm, find the area of ∆AOD.​

Answer 1

Answer:

triangle OAD ~ triangle OBC (AA SIMILARLY)

ar(AOD)/ar(BOC)= AD^2/BC^2

ar(AOD) = 7^2×150/5^2

= 49×150/25

= 49×6

= 294 sq.cm

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