Question

In the figure D and E are the points on the base BC of triangle ABC such that BD= CE and AD=AE prove that triangle ABD is congruent to truangle ACE

Answer 1

Answer:

Step-by-step explanation:

In ΔADE,

AD=AE

∠ADE= ∠AED [angles opposite to equal sides]  -----[1]

∠ADB= 180°-∠ADE [linear pair]

∠AEC= 180°-∠AED [linear pair]

from [1]: 180°-∠ADE = 180°- ∠AEC

             ∴∠ADB = ∠AEC

AD=AE[given]

∠ADB=∠AEC [proved]

BD=CE[given]

By rule of SAS, ΔABD ≅ ΔACE