in the figure, D and E arepoints on the base of triangle ABC such that BD=CE and AD=AE. prove that AB=AC
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in Δade,
ad=ae
∠aed=∠ade
180-∠aed=180-∠ade
∠aec=∠adb
in Δabd and Δace,
ad=ae
∠adb=∠aec
bd=ce
Δabd is congrunt to Δace (asa)
ab=ac (cpct)
ad=ae
∠aed=∠ade
180-∠aed=180-∠ade
∠aec=∠adb
in Δabd and Δace,
ad=ae
∠adb=∠aec
bd=ce
Δabd is congrunt to Δace (asa)
ab=ac (cpct)
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