Question

in the figure, Db is perpendicular to Bc and de is perpendicular to ab and ac is perpendicular to bc prove that be/ de = ac/bc.​

Answer 1

Answer:

please click whole fig.

Step-by-step explanation:

HOPE IT HELPS,

PLEASE RATE, THANK AND MARK AS BRAINLIEST.

Answer 2

⌬ Correct Question:-

in the figure,DB is perpendicular to BC and DE is perpendicular to AB and AC is perpendicular to BC prove that BE/ DE = AC/BC.

⌬ Given:-

•In the given figure DB⏊BC; DE⏊AB and AC⏊BC

⌬ To Prove:-

•BE/DE=AC/BC

⌬ Proof:-

DB⏊BC

Therefore, ∠DBC=90⁰

==>∠DBE+∠ABC=90⁰ ____( 1 )

AC⏊BC

Therefore, ∠ACB=90⁰

==>∠ABC+∠BAC=90⁰ ____( 2 )

In view of (1) and (2)

∠DBE=∠BAC. ____( 3 )

In ΔDEB and ΔBCA

∠DEB=∠BCA [Each =90⁰]

∠DBE=∠BAC [From (3) ]

Therefore ,

ΔDEB∼ΔBCA. [ AA similarities]

Therefore,

BE/AC=DE/BC [ Corresponding sides of two similar triangles are proportional]

==> BE/DE=AC/BC

Hence, Proved