in the figure DE||BC and MF||AB find
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Produce ED to F. Now EF∥CB
⇒ ∠DFA=∠CBF=118
o
(corr. ∠s)
In △DEAF, ∠ADF=180
o
−(118
o
+42
o
)
180
o
−160
o
=20
o
∠ADE=180
o
−∠ADF=180
o
−20
o
Therefore, ∠ADE=160
o
(Linear pair)
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