Question

In the figure Dell BC , LA-40 and
CB=60 find the values of xys
2​

Answer 1

$ANSWER</p><p></p><p>In△BCE</p><p></p><p>⟹∠BEC+∠BCE+∠CBE=180∘</p><p></p><p>⟹90∘+30∘+∠CBE=180∘</p><p></p><p>⟹∠CBE=60∘</p><p></p><p>y=60∘</p><p></p><p>In△APC:</p><p></p><p>⟹50∘+30∘+∠APC=180∘</p><p></p><p>⟹∠APC=100∘</p><p></p><p>∴x=180−∠APC</p><p></p><p>(∵sumofanglesonastraightline=180∘)</p><p></p><p>⟹x=180∘−100∘=80∘</p><p></p><p>In△BOP:</p><p></p><p>z=x+y(exteriorangleofatriangle=sumoftwooppositeinteriorangles)</p><p></p><p>⟹z=80+60=140∘</p><p></p><p>∴x=80∘,y=60∘,z=140∘</p><p></p><p>$

this is your answer dear plz