Question

In the figure, find four angles A,B,C and D of the parallelogram ABCD.
Figure is shown above.
Plz tell fast.
Your answer should be :-
90° each.
Please give full explanation.​​

Answer 1

Step-by-step explanation:

2x+5x+3x=360

or,10x=360

or,x=36

x=36°

four angles of parallelogram is 36°,72°,108°,360°-216°=144°

Answer 2

Step-by-step explanation:

Here,

In triangle BDC,

∠BDC+∠DBC+∠BCD=180(sum of interior angles of a triangle is 180°)

or, 2x+3x+5x=180°

or, 10x=180°

i.e. x=18°

So, ∠DCB=5x=5×18°=90°

Now,

∠DAB = ∠DCB(opposite angles of a parallelogram are equal)

= 90°

And,

∠DAB+∠ADC=180°(being co-interior angle)

or, 90+∠ADC=180°

or, ∠ADC=180°-90°

i.e. ∠ADC= 90°

Similarly, ∠ABC=∠ADC(opposite angles of a parallelogram are equal)

=90°

Hence,

∠ABC=∠DCB=∠ADC=∠DAB=90°