In the figure find the length of an arc AB of a circle centre O if AOB = 90^o
Answers
Answer:(1) In the given figure, OA and OB are the radii of the circle. OA=OB=AB (Given) ∴△OAB is an equilateral triangle. ⇒∠AOB=∠OAB=∠OBA=60 o Thus, the measure of ∠AOB is 60 o . (2) The measure of an angle subtended by an arc at a point on the circle is half of the measure of the angle subtended by the arc at the centre. ∠ACB= 2 1 ∠AOB= 2 1 60o=30 o Thus, the measure of ∠ACBis30 o . (3) m(arcAB)=∠AOB=60 o (Measure of an arc is the measure of its corresponding central angle) Thus, the measure of arc AB is 60 o . (4) m(arcACB)=360 o - m(arcAB)=360 o −60 o =300 o Thus, the measure of arc ACB is 300 o .
Given:
Angle AOB = 90°
To find:
Length of the arc AB
Solution:
The required length is 11 cm.
We can obtain the length by using the following formula as it forms a part of the circle's circumference.
The required length of the arc=Angle AOB/360°×2πR
The circle's radius=R=7 cm
Using the values, we get
The required length of the arc=90°/360°×2×22/7×7
=1/4×44
=44/4
=11 cm
Therefore, the required length is 11 cm.