Question

In the figure find the value of A square +B square+C square+D square +E square + F square ​

Answer 1

Answer:

But, where is figure????????????

Answer 2

(a+b+c)

2

=a

2

+b

2

+c

2

+2(ab+bc+ca)

Therefore 0

2

=q+2(ab+bc+ca)

⇒ab+bc+ca=

2

−q

⟶(1)

Now, (a

2

+b

2

+c

2

)

2

=a

4

+b

4

+c

4

+2(a

2

b

2

+b

2

c

2

+c

2

a

2

) (all squared )

⇒q

2

=r+2 ( some positive number )

⇒(ab+bc+ca)

2

=a

2

b

2

+b

2

c

2

+c

2

a

2

+2(ab

2

c+a

2

bc+abc

2

)

⇒

4

q

2

−2=a

2

b

2

+b

2

c

2

+c

2

a

2

∴a

2

b

2

+b

2

c

2

+c

2

a

2

<

4

q

2

∴q

2

<r+2(

4

q

2

)

⇒q

2

<r+

2

q

2

⇒

2

q

2

<r

⇒q

2

<2r