In the figure given above , D is any point on the side BC of triangleABC . If AB>AC , show that AB>AD.
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As D is any point on the side BC , take AD as the line which meets line BC at right angle
Now, From the ∆le ABD angle D is 90°
So, From this AB becomes the hypotenuse
Therefore AB will be absolutely greater than AD and BD induvidually.
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