in the figure given below a b equal to DC and ac equal to DB is triangle ABC equal to triangle DCB
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In triangle Abc and triangle Dcb
angle ABC =angle Dcb ( because Ab=Dc, Ac=Db so it is a rectangle and angle b= angle c =90° )
AC=DB ( given)
∆ Abc congruent to ∆ Dcb by RHS
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yes by sss rule
in triangle abc and triangle dcb
ab=dc. (given)
ac=db ( given)
bc =bc ( common)
by sss triangle abc=to triangle dcb
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hope it help
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