Math, asked by ddz74391, 7 days ago

In the figure given below, ABC is a triangle. BC is parallel to AE. If BC = AC, then what is the value of ∠CAE?
A. 20°
C. 40°
B. 30°
D. 50° ​

Answers

Answered by ᏢerfectlyShine
0

Answer:

BC is parallel to AE. If BC = AC, then what is the value of ∠CAE? Hence, ΔABC is an isosceles triangle. ⇒115° = x + 65° ⇒ x = 50°.Answer D

Step-by-step explanation:

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