In the figure given below, ABC is a triangle. BC is parallel to AE. If BC = AC, then what is the value of ∠CAE?
A. 20°
C. 40°
B. 30°
D. 50°
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BC is parallel to AE. If BC = AC, then what is the value of ∠CAE? Hence, ΔABC is an isosceles triangle. ⇒115° = x + 65° ⇒ x = 50°.Answer D
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