In the figure given below, if ABCD is a square of side 14cm and APB and DPC are semicircle. Find the area of shaded region
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Answer:
42cm²
Step-by-step explanation:
ALSO APD AND BPC ARE SEMI CIRCLE THEREFORE
THEIR RADIUS R=24/2=7CM
NOW AREA OF SEMI CIRCLE APD
AREA OF SEMI CIRCLE =PI R²/2
=22/7(7)²
=77CM²
AND ARE OF SQUARE ABCP=SIDE²=14²=196cm²
hence =196-*77+77)=42cm²
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