In the figure given below point 'O' is the centre of the circle. If radius of the circle is 7 cm and the measure of angle POQ is 60 degree then , find area of the cricle
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Answer:
Radius OP=OQ=r=12 CM
θ=30
and PM is perpendicular to OQ
Area of a sector of a circle OPQR =πr
2
(
360
θ
)
=3.14×(12)
2
×(
360
30
)
=37.68 cm
2
Area of △OQP=
2
1
×OQ×PM
=
2
1
×12×OP×sin30
=
2
1
×12×12×
2
1
=36 cm
2
Area of segment PRQ = (Area of a sector of a circle OPQR) - (Area of △OQP)
=(37.68−36)cm
2
=1.68 cm
2
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