Question

In the figure given below PS is the diameter, points P, Q, R and T, S, R are collinear. QTS is 6xk find k

Answer 1

Internal radius of the pipe , r = 1 cm .

→ Length of water flowing in 1 sec , h = 80 cm .


▶ Then, Volume of water flowing in 1 second 

= πr²h .

= ( π × 1 × 1 × 80 ) cm³ .

= 80π cm³ .


▶ Volume of water flowing in 30 minutes [ Half an hour ] 

= ( 80π × 60 × 30 ) cm³ .

= 144,000π cm³ .


→ Radius of cylindrical tank, R = 40 cm .

Let the rise in level of water be H cm .


▶ Volume of water in the tank 

= πR²H .

= ( π × 40 × 40 × H ) cm³ .

= 1600πH cm³ .


▶ Volume of water in the tank = Volume of water flown through a pipe .

\begin{lgathered}\textsf \implies 1600 \cancel\pi H = 144000 \cancel\pi . \\ \\ \implies H = \frac{144000}{1600} = \frac{ \cancel{1440} \: \: ^{90} }{ \cancel{16}} . \\ \\ \huge \boxed{ \boxed{ \pink{ \therefore H = 90 \sf cm.}}}\end{lgathered}⟹1600π​H=144000π​.⟹H=1600144000​=16144090​.∴H=90cm.​​​ 


✔✔ Hence, rise in level = 90 cm ✅✅ .


THANKS

Answer 2

Answer:

Internal radius of the pipe , r = 1 cm .

→ Length of water flowing in 1 sec , h = 80 cm .

▶ Then, Volume of water flowing in 1 second 

= πr²h .

= ( π × 1 × 1 × 80 ) cm³ .

= 80π cm³ .

▶ Volume of water flowing in 30 minutes [ Half an hour ] 

= ( 80π × 60 × 30 ) cm³ .

= 144,000π cm³ .

→ Radius of cylindrical tank, R = 40 cm .

Let the rise in level of water be H cm .

▶ Volume of water in the tank 

= πR²H .

= ( π × 40 × 40 × H ) cm³ .

= 1600πH cm³ .

▶ Volume of water in the tank = Volume of water flown through a pipe .

✔✔ Hence, rise in level = 90 cm ✅✅ .

THANKS

may god bless you