Question

In the figure given figure find
(1) angle SQR (2)angle QSR. (3) angle SQP​

Answer 1

Answer:

∠QSR = 35°

∠SQP = 35°

∠SQR = 65°

Step-by-step explanation:

here, SR ║PQ and SQ is transversal.

so, ∠QSR = ∠SQP               [alternate interior angles]

and, ∠PSQ = ∠SQR             [alternate interior angles]

∵ ∠PSQ = ∠SQR = 65°

now, ∠PSQ + ∠SQP + ∠QPS = 180°     [angle sum property of Δ]

      = 65° + ∠SQP + 80° = 180°

      = ∠SQP = 180° - 145°

      = ∠SQP = 35°

∵ ∠QSR = ∠SQP  = 35°

hope it will help you.

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Answer 2

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