Question

In the figure I and m are two parallel lines intersected by another pair of parallel
lines p and q. Show that tiangle ABC = triangleCDA.​

Answer 1

Answer:

Hello my friend here is the answer.

Step-by-step explanation:

Given,

l || m and p || q

To prove,

ΔABC ≅ ΔCDA

Proof,

In ΔABC and ΔCDA,

∠BCA =∠DAC

(Alternate interior angles as p||q)

AC = CA (Common)

∠BAC =∠DCA

(Alternate interior angles as l ||m)

Hence, ΔABC ≅ ΔCDA (by ASA congruence rule.)

Hope this helps!!!