Question

In the figure, if AB=CD and ∠AOB=90° find ∠COD

Answer 1

since, AB = CD
AO = BO
ΔAOB is an isosceles triangle
similarly, ΔCOD is an isosceles triangle
angle AOB = angle COD

Answer 2

Answer:

∠COD=90°

Step-by-step explanation:

In Δ BOA and ΔCOD

AB = CD(Given)

OA = OD( radii of the circle)

OB = OC ( radii of the circle)

So, Δ BOA is congruent to triangles  ΔCOD by SSS property

Now ∠BOA=∠COD=90°

Since corresponding angles of congruent triangles are equal

So, ∠BOA=∠COD=90°

Hence ∠COD=90°