Math, asked by angelbenjamin39208, 1 year ago

In the figure if AC is bisector of angle BAD such that AB=3 cm and AC=5 cm, then What is CD equal to.

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Answers

Answered by bharat9291
211
in triangle BAC and DAC
AC = AC
angle B = angle D
angle BAC = angle DAC
by AAS CRITERIA
triangle BAC is congurent to triangle DAC
by CPCT
AD = BC = 3 cm
in triangle ACD
(AC) ^ 2 = ( CD) ^2 + ( AD)^2
(5)^2 = (CD)^2 + ( 3)^2
25-9 = (CD) ^2
CD = √16 = 4 CM
Answered by amitnrw
5

Given  : AB = 3 cm and AC = 5 cm

AC is bisector of angle BAD

To Find : CD

(a) 4 cm

(b) 2 cm

(c) 3 cm

(d) 5 cm​

Solution:

ΔABC is right angle

Pythagoras  theorem:  

Square on the hypotenuse of a right-angled triangle is equal to the  

sum of the squares of the other two perpendicular sides.

AC² = AB² + BC²

=> 5² = 3² + BC²

=> BC² = 4²

=> BC = 4 cm

in Δ ABC and ΔADC

∠BAC = ∠DAC  as  AC is bisector of angle BAD

∠ABC = ∠ADC = 90°

AC = AC   common

=> ΔABC ≅ ΔADC  using AAS congruence

Hence

BC = CD   using corresponding parts of congruent triangles are equal

Hence , CD = 4 cm

Correct option is  a) 4 cm

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