Question

In the figure, if B1, B2, B3,…... and A1,A2, A3,….. have been marked at

equal distances. In what ratio C divides AB?​

Answer 1

$\cancel\dfrac{ \frac{ \frac{ \frac{ \frac{ \frac{ \frac{ \frac{ \frac{ \frac{3 \times \frac{3}{3} }{3} \times \frac{3}{3} }{3} \times \frac{3}{3} }{3} \times \frac{3}{3} }{3} \times \frac{3}{3} }{3} \times \frac{3}{3} }{3} \times \frac{3}{3} }{3} \times \frac{3}{3} }{3} \times \frac{3}{3} }{3} \times \frac{3}{3} }{3} \times \frac{3}{3} =0$

Answer 2

Answer:

C divides AB in the ratio 8:5

Step-by-step explanation:

As shown in the attached figure

If we draw lines parallel to  from points  and  respectively

Also if we draw lines parallel to  from points  and  respectively

Then we can clearly see that CB contains 5 parts and CA contains 8 parts

Therefore, point C divides AB in the ratio 8:5[/tex]