Question

in the figure if lines PQ and RS intersect at point P such that angle PRT equals to 40 degree angle RPT equals to 95 degree and Angle TSQ equals to 75 degree find angle SQT​

Answer 1

Hello mate ☺

____________________________

Solution:

In ∆PRT, we have

∠PRT+∠RPT+∠RTP=180°   (Sum of three angles of a triangle =180°)

⇒40°+95°+∠RTP=180°

⇒∠RTP=180°−40°−95°=45°

∠RTP=∠QTS     (Vertically Opposite Angles)

Therefore, ∠QTS is also equal to 45°

In ∆STQ, we have

∠SQT+∠TSQ+∠QTS=180°  (Sum of three angles of a triangle =180°)

⇒∠SQT+75°+45°=180°

⇒∠SQT=180°−75°−45°=60°

I hope, this will help you.☺

Thank you______❤

_____________________________❤

Answer 2

Answer:

<SQT = 60

Step-by-step explanation:

The answer is in the picture given