in the figure if <AOC +<BOC = 70° , find < COD
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Lines and Angles
Pair of Angles
In the given figure, lines ...
MATHS
In the given figure, lines AB and CD intersect at O.If ∠AOC+∠BOE=70
∘
and ∠BOD=40
∘
find ∠BOE and reflex of ∠COE
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Given:∠BOD=40
∘
Since AB and CD intersects, ∠AOC=∠BOD(vertically opposite angles)
∠AOC=40
∘
Also,∠AOC+∠BOE=70
∘
⇒∠BOE=70
∘
−∠AOC=70
∘
−40
∘
=30
∘
We need to find reflex∠COE
Reflex∠COE=360
∘
−∠COE
Now, ∠AOC+∠COE+∠BOE=180
∘
⇒∠COE+(∠AOC+∠BOE)=180
∘
⇒∠COE+(40
∘
+30
∘
)=180
∘
⇒∠COE=180
∘
−70
∘
=110
∘
Reflex∠COE=360
∘
−110
∘
=250
∘
Answered By
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