Question

in the figure if PQ perpendicular QR then x is equal to​

Answer 1

Given :-

• PQ ⟂ QR .
• ∠TSR = x°
• ∠STR = (x + 16)°
• Ext. ∠S = 28°

To Find :-

• ∠x = ?

Solution :-

→ ∠TSQ = 28° (vertically opposite angle.)

then, in Right ∆SQT, (since PQ ⟂ QR => PQ ⟂ QT) .

→ ∠SQT + ∠TSQ + ∠STQ = 180° (angle sum property.)

→ 90° + 28° + (x + 16)° = 180°

→ 118° + 16° + x° = 180°

→ 134° + x° = 180°

→ x° = 180° - 134°

→ x° = 46° (Ans.)

Learn more :-

In ABC, AD is angle bisector,

angle BAC = 111 and AB+BD=AC find the value of angle ACB=?

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