In the figure, if x/3 = y/4 = z/5 calculate x, y and z (CBSE Grade 9, 2015)
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Answered by
103
Given,
= x/3 = y/4 = z/5
i, e y = z = 4x/3 and 5x/3
∵ A,B ,C and D forms a cyclic quadrilateral.
∴ ∠ABC + ∠CDA = 180°....(1)
( Also, ∠CDQ + ∠CDA = 180°...(ii)
From (i) and (ii), ∠ABC = ∠CDQ
Also, ∠PCB = x... [Vertically opp angles Now,
In △ CDQ, x + y + ∠CDQ = 180° ⇒ x + z + ∠ABC = 180° ⇒ x + z + (180° − ∠PBC) = 180
⇒ x + z = ∠PBC
⇒ x + z = (180° − x − y)
⇒ 2x + y + z = 180°
⇒ 2x + + = 180° 4x/3 + 5x/3
⇒ 6x+4x+5x/3 = 180° 6x+4x+5x 3
⇒ 5x = 180°
⇒ x = 36°
y = 4x/3 = 48°
z = 5x/3 = 60°
= x/3 = y/4 = z/5
i, e y = z = 4x/3 and 5x/3
∵ A,B ,C and D forms a cyclic quadrilateral.
∴ ∠ABC + ∠CDA = 180°....(1)
( Also, ∠CDQ + ∠CDA = 180°...(ii)
From (i) and (ii), ∠ABC = ∠CDQ
Also, ∠PCB = x... [Vertically opp angles Now,
In △ CDQ, x + y + ∠CDQ = 180° ⇒ x + z + ∠ABC = 180° ⇒ x + z + (180° − ∠PBC) = 180
⇒ x + z = ∠PBC
⇒ x + z = (180° − x − y)
⇒ 2x + y + z = 180°
⇒ 2x + + = 180° 4x/3 + 5x/3
⇒ 6x+4x+5x/3 = 180° 6x+4x+5x 3
⇒ 5x = 180°
⇒ x = 36°
y = 4x/3 = 48°
z = 5x/3 = 60°
Answered by
52
x/3 = y/4 = z/5
A,B ,C and D forms a cyclic quadrilateral.
∠ABC + ∠CDA = 180°_____1
( Also, ∠CDQ + ∠CDA = 180°________2
From (1) and (i2)
∠ABC = ∠CDQ
Also, ∠PCB = x(Vertically opp angles)
In △ CDQ, x + y + ∠CDQ = 180°
⇒ x + z + ∠ABC = 180°
⇒ x + z + (180° − ∠PBC) = 180
⇒ x + z = ∠PBC
⇒ x + z = (180° − x − y)
⇒ 2x + y + z = 180°
⇒ 2x + + = 180° 4x/3 + 5x/3
⇒ 6x+4x+5x/3 = 180° 6x+4x+5x 3
⇒ 5x = 180°
⇒ x = 36°
y = 4x/3 = 48°
z = 5x/3 = 60°
A,B ,C and D forms a cyclic quadrilateral.
∠ABC + ∠CDA = 180°_____1
( Also, ∠CDQ + ∠CDA = 180°________2
From (1) and (i2)
∠ABC = ∠CDQ
Also, ∠PCB = x(Vertically opp angles)
In △ CDQ, x + y + ∠CDQ = 180°
⇒ x + z + ∠ABC = 180°
⇒ x + z + (180° − ∠PBC) = 180
⇒ x + z = ∠PBC
⇒ x + z = (180° − x − y)
⇒ 2x + y + z = 180°
⇒ 2x + + = 180° 4x/3 + 5x/3
⇒ 6x+4x+5x/3 = 180° 6x+4x+5x 3
⇒ 5x = 180°
⇒ x = 36°
y = 4x/3 = 48°
z = 5x/3 = 60°
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