Math, asked by sahanisahaniad911, 4 months ago

In the figure in triangle abc p parallel to q
. PQ : BC = 1:3.
Then find the ratio of AP and PB

Answers

Answered by nishith2909
0

Answer:

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Answered by vinshultyagi
2

\Huge{\color{blue}{\underline{\underline{Given:-}}}}

In triangle ABC, PQ parallel to BC.

The ratio of PQ : BC = 1:3

AS,

The corresponding sides of two similar triangles are proportional to each other.

\Huge{\color{blue}{\underline{\underline{TO \:Find:-}}}}

The ratio of AP and PB

\Huge{\color{blue}{\underline{\underline{Answer:-}}}}

In triangle APQ and triangle ABC,

\angle A=\angle A----(Common)

\sf \angle{APQ}=\angle{ABC}--(corresponding Angles)

So, by AA similarity,

\triangle APQ\sim\triangle ABC

\sf So, \dfrac{AP}{AB}=\dfrac{PQ}{BC}

Put the value into the formula

\dfrac{AP}{AP+PB}=\dfrac{1}{3}

\sf 3AP=AP+PB\\ \sf 3AP-AP=PB\\ \sf 2AP=PB

\sf \dfrac{AP}{PB}=\dfrac{1}{2}

Hence, The ratio of AP and PB is 1:2

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