Question

In the figure it is given that AD parallel to BC prove that area of triangle CGD = area of triangle ABG

Answer 1

Answer:

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Answer 2

Answer with Step-by-step explanation:

In quadrilateral ABCD

AD is parallel to BC

When two triangles are formed between same parallel lines and lie on the same base then their area are equal.

The triangle ADC and triangle ABD lie on the same base AD and formed between same parallel lines AD and BC.

Therefore,

Area of triangle ADC =Area of triangle ABD

Ar(ADC)-ar(AGD)=Ar(ABD)-ar(AGD)

Ar(CGD)=Ar(ABG)

Area of triangle CGD=Area of triangle ABG

Hence, proved.

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