Question

in the figure it is given that BR=PC qnd <ACB=<QRP and AB//PQ prove that AC=QR

Answer 1

given
<ACB=<QRP
BR=PC
AB||PQ
in triangle ABC and PQR
<ACB=<QRP
<ABC =<QPR (PQ||AB ; alternate interior angle )
BR=PC
so triangle ABC is congruent to triangle PQR BY ASA
AC=QR(by CPCT)