In the figure LM || CB and LN || CD.
Prove that AM/AB = AN/AD
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Answered by
15
ANSWER
In △ABC,
LM∥BC
∴ By proportionality theorem,
AB
AM
=
AC
AL
............(1)
Similarly,
In △ADC,
LN∥CD
∴ By proportionality theorem,
AD
AN
=
AC
AL
............(2)
∴ from (1) and (2),
AB
AM
=
AD
AN
Answered by
7
In the given figure, we can see, LM || CB,
By using basic proportionality theorem, we get,
AM/MB = AL/LC …..(i)
Similarly, given, LN || CD and using basic proportionality theorem,
∴ AN/AD = AL/LC ……(ii)
From equation (i) and (ii), we get,
AM/MB = AN/AD
Hence, proved.
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