Question

In the figure <A= 65 , L<ABC = 56 and
BO, CO are the bisector of angles <ABC
and <BCA respectively then find <OCB
and <BOC.​

Answer 1

Answer:

<OCB= 29°

<BOC= 123°

Step-by-step explanation:

<ACB = 180 - (65 + 56)

= 180 - 122

= 58°

<OCB = 1/2 <ACB

= 1/2 × 58

= 29°

<BOC = 180 - (<OCB + <OBC)

= 180 - (29 + 28)

= 180 - 57

= 123°