Question

in the figure <abq = 110 and <acr = 130​

Answer 1

So, by linear pair

<abq + <abc = 180

110 + < abc = 180

< abc = 180-110

< abc = 70

By linear pair

< acr + < acb = 180

130 + < acb =180

< acb = 180-130

< acb = 50

< acb + < abc + < bac = 180 ( sum of all angles of a triangle is 180)

50 + 70+ < bac = 180

120 + < bac = 180

< bac = 180 -120

< bac = 60

< A = 60 , < B =70 , < C = 50

HERE IS YOUR ANSWER DEAR. PLEASE MARK ME AS BRAINLIST

Answer 2

Hey mate here is your answer

# angle ABQ + angle ABC = 180 ( linear pair)

# 110 + ABC = 180

# ABC = 180 - 110

# ABC = 70

# angle ACR + angle ACB = 180 ( linear pair)

# 130 + ACB = 180

# ACB = 180 - 130

# ACB = 50

# angle A + angle B + angle C = 180 (angle sum property)

# A + B + C = 180

# A + 70 + 50 = 180

# A + 120 = 180

# A = 180 - 120

# A = 60

A = 60 , B = 70 , C = 50

Hope it helps you

Thank you