Question

in the figure m angle QPR=90° seg PM perpendicular to seg QR Q- M-R , PM=12,QM= 8 find QR​

Answer 1

REFER TO THE ATTACHMENT

Answer 2

We know that,

In a right angled triangle, the perpendicular segment to the hypotenuse from the opposite vertex, is the geometric mean of the segments into which the hypotenuse is divided.

Here, seg PM ⊥ seg QR

∴ PM²=QM×MR

⇒10²=8×MR

⇒100=8×MR

⇒MR=1008

⇒MR=252

Now,QR=QM+MR

=8+252

=16+252

=412

=20.5

Hence, QR = 20.5