Question

In the figure, ma = 2 kg and mb = 4 kg.
For what minimum value of F, A starts
slipping over B : (g = 10 m/s2)​

Answer 1

Explanation:

Let maximum friction is acting f=0.5×2×10=10N

and both the block as a acceleration a

in A block 

F-f=2a  ...eq(1)

in B block 

f=2a... eq(2)

and f=10N

from eq(2)

 a=5ms−2

from eq(1)

F=2×5+10=20N

Hence the D option is correct.  

Answer 2

Answer:

36 N

Explanation:

This is the correct Answer

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