Question

Two Containers A and B contain molecular gas at same temperature with masses of molecules are Ma and Mb then relation of momentum Pa and Pb will be​

Answer 1

Answer:

Momentum of a particle p = Mass(M) × RMS velocity(V)

V= k÷√M

Va= k÷ √Ma

Vb= k÷√Mb

k is same for both as the temperature is constant k=√3×R×T

Pa= Ma×Va= √Ma×k

Pb= Mb×Vb= √Mb×k

Pa: Pb= √Ma:√Mb

Answer 2

Answer:

$\dfrac{P_A}{P_B}=\sqrt{\dfrac{M_A}{M_B}}$

Explanation:

Given that

Container A - mass = Ma

Container B - mass = Mb

T is same for both the container.

We know that velocity of gas given as

$v=\sqrt{\dfrac{\gamma RT}{M}}$

Momentum P= M. v

$P=M\sqrt{\dfrac{\gamma RT}{M}}$

So we can say that

$P\alpha \sqrt M$

So

$\dfrac{P_A}{P_B}=\sqrt{\dfrac{M_A}{M_B}}$